Initial velocity equation: (speed(ft/sec))cos(launch angle)
Quadratic Model: h= -16t^2+vot+ho
A cannonball is shot upward from the upper deck of a fort with an initial velocity of 192 feet per second. The deck is 32 feet above the ground.
1. Type the model into your calculator in "Y=."
2. Graph.
3. Go to table and see how high the number in the "Y" axis goes; it will be 608.
4. 608 feet is how high the cannonball will go.
5. Scroll down the table to where the "Y" axis is closest to zero; it will be between 12 and 13.
6. The cannonball is in the air for 12 seconds.
Nice job, you explained it very clearly and I'm glad you got the same answers as I did!
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