Thursday, February 3, 2011

Math Component

Initial velocity equation: (speed(ft/sec))cos(launch angle)
Quadratic Model: h= -16t^2+vot+ho
A cannonball is shot upward from the upper deck of a fort with an initial velocity of 192 feet per second. The deck is 32 feet above the ground.

1. Type the model into your calculator in "Y=."
2. Graph.
3. Go to table and see how high the number in the "Y" axis goes; it will be 608.
4. 608 feet is how high the cannonball will go.
5. Scroll down the table to where the "Y" axis is closest to zero; it will be between 12 and 13.
6. The cannonball is in the air for 12 seconds.

1 comment:

  1. Nice job, you explained it very clearly and I'm glad you got the same answers as I did!

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